Dear friends In this video lecture I will discuss the combined divisibility rule of 7,11 and 13. Now by saying the combined divisibility rule of 7,11 and 13 & 7,11 and 13 are co-prime with each other so it is equivalent to the divisibility rule of 1001 which is the product of these three co-primes 7,11 and 13. The proving of these divisibility rules method is being showed in this video lecture.

In case you have doubts post them in the comment section below.

amazing.....u r just genius.

ReplyDeletei have gone through these lectures till now and what ever quarry comes in my mind, the same is taken just then.

THANK YOU from the core of my heart.....ur lectures made me feel like school days, when we enjoy the math problems.

Thank you for your good words Ashish..

ReplyDeletesir how to download this video

ReplyDeletesir how to download these videos

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ReplyDeletethanks sir

ReplyDeletethank you sir.......

ReplyDeleteThanku sir nice concise explanation

ReplyDeleteSir Can you please help with this problem

ReplyDeleteLet say I have taken a number 713256

Now I'm checking its remainder when divided by 11

As you said in order to check its remainder do the following that is

(-713 + 256 )/ 11 = -457/11 , Now on dividing it I get remainder as 6

But when I divide the number i.e 713256 I get remainder as 5

Why so ? Kindly help me out

on dividing -457/11 you get -6 as rem which when added to 11 gives u a positive remainder 5

DeleteWhile u r checking ur remainder, u must hav got -6. Which means (11-6) = 5 is ur real remainder (because we cannot take remainder in negative sign).

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